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When the following compound is treated with sodium methoxide in methanol, two
Chapter 7, Problem 7-76(choose chapter or problem)
When the following compound is treated with sodium methoxide in methanol, two elimination products are possible. Explain why the deuterated product predominates by about a 7:1 ratio (refer to 7-75). C C Br C C H D D H H H H C C H H H 87% 13%
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QUESTION:
When the following compound is treated with sodium methoxide in methanol, two elimination products are possible. Explain why the deuterated product predominates by about a 7:1 ratio (refer to 7-75). C C Br C C H D D H H H H C C H H H 87% 13%
ANSWER:Step 1 of 2
The elimination reaction is the reaction in which two atoms get eliminates, resulting in a double bond formation. The mechanism can be consist of one-step or two-step. The one step mechanism is a mechanism in which both atoms get eliminated in one step. The mechanism has two stages; first carbocation formation, then deprotonation.