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When the following compound is treated with sodium methoxide in methanol, two

Chapter 7, Problem 7-76

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QUESTION:

When the following compound is treated with sodium methoxide in methanol, two elimination products are possible. Explain why the deuterated product predominates by about a 7:1 ratio (refer to 7-75). C C Br C C H D D H H H H C C H H H 87% 13%

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QUESTION:

When the following compound is treated with sodium methoxide in methanol, two elimination products are possible. Explain why the deuterated product predominates by about a 7:1 ratio (refer to 7-75). C C Br C C H D D H H H H C C H H H 87% 13%

ANSWER:

Step 1 of 2

The elimination reaction is the reaction in which two atoms get eliminates, resulting in a double bond formation. The mechanism can be consist of one-step or two-step. The one step mechanism is  a mechanism in which both atoms get eliminated in one step. The  mechanism has two stages; first carbocation formation, then deprotonation.

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