Solution Found!
Finding Surface AreaFind the surface area of the cone
Chapter 6, Problem 12E(choose chapter or problem)
Find the surface area of the cone frustum generated by revolving the line segment \(y=(x/2)+(1/2),\ 1\le x\le3\), about the y-axis. Check your result with the geometry formula
Frustum surface area \(=\pi\left(r_{1}+r_{2}\right) \times\) slant height.
Equation Transcription:
Text Transcription:
y=x/2+(1/2), 1 leq x leq 3
= (r_1 + r_2) times
Questions & Answers
QUESTION:
Find the surface area of the cone frustum generated by revolving the line segment \(y=(x/2)+(1/2),\ 1\le x\le3\), about the y-axis. Check your result with the geometry formula
Frustum surface area \(=\pi\left(r_{1}+r_{2}\right) \times\) slant height.
Equation Transcription:
Text Transcription:
y=x/2+(1/2), 1 leq x leq 3
= (r_1 + r_2) times
ANSWER:
SOLUTION
Step 1
Here, we have to find the lateral surface area of the cone generated by revolving the line segment about the y-axis.