A basketball team consists of 6 frontcourt and 4 back-court players. If players are divided into roommates at random, what is the probability that there will be exactly two roommate pairs made up of a backcourt and a frontcourt player?
Step 1 of 2:
It is given that in a basketball team there are 6 frontcourt players and 4 backcourt players.The players are to be divided into roommates at random.
We have to find the probability that exactly two roommate pairs have one frontcourt player and one backcourt player.