Problem 12STE

A basketball team consists of 6 frontcourt and 4 back-court players. If players are divided into roommates at random, what is the probability that there will be exactly two roommate pairs made up of a backcourt and a frontcourt player?

Solution:

Step 1 of 2:

It is given that in a basketball team there are 6 frontcourt players and 4 backcourt players.The players are to be divided into roommates at random.

We have to find the probability that exactly two roommate pairs have one frontcourt player and one backcourt player.