Ninety-eight percent of all babies survive delivery.

Chapter 3, Problem 16P

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QUESTION:

Problem 16P

Ninety-eight percent of all babies survive delivery. However, 15 percent of all births involve Cesarean (C) sections, and when a C section is performed, the baby survives 96 percent of the time. If a randomly chosen pregnant woman does not have a C section, what is the probability that her baby survives?

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QUESTION:

Problem 16P

Ninety-eight percent of all babies survive delivery. However, 15 percent of all births involve Cesarean (C) sections, and when a C section is performed, the baby survives 96 percent of the time. If a randomly chosen pregnant woman does not have a C section, what is the probability that her baby survives?

ANSWER:

Step 1 of 2

Let us denote S be the event of survival.

Let C denotes the probability of cesarean.

Given that,

                        P(S) = 0.98

                      

                                = 1- 0.98

                                = 0.02

                      P(C) = 0.15

                     

                                  = 1-0.15

                                  = 0.85

                       

 

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