Solution Found!
Ninety-eight percent of all babies survive delivery.
Chapter 3, Problem 16P(choose chapter or problem)
Problem 16P
Ninety-eight percent of all babies survive delivery. However, 15 percent of all births involve Cesarean (C) sections, and when a C section is performed, the baby survives 96 percent of the time. If a randomly chosen pregnant woman does not have a C section, what is the probability that her baby survives?
Questions & Answers
QUESTION:
Problem 16P
Ninety-eight percent of all babies survive delivery. However, 15 percent of all births involve Cesarean (C) sections, and when a C section is performed, the baby survives 96 percent of the time. If a randomly chosen pregnant woman does not have a C section, what is the probability that her baby survives?
ANSWER:
Step 1 of 2
Let us denote S be the event of survival.
Let C denotes the probability of cesarean.
Given that,
P(S) = 0.98
= 1- 0.98
= 0.02
P(C) = 0.15
= 1-0.15
= 0.85