Prove:tan1 x + tan1 y = tan1 x + y1 xy provided /2 < tan1 x + tan1 y</2. [Hint: Use

Chapter 0, Problem 59

(choose chapter or problem)

Prove:

$\tan ^{-1} x+\tan ^{-1} y=\tan ^{-1}\left(\frac{x+y}{1-x y}\right)$

provided $-\pi / 2<\tan ^{-1} x+\tan ^{-1} y<\pi / 2$. [Hint: Use an identity for $\tan (\alpha+\beta)$.]

Equation Transcription:

$ta{n}^{-1}x+ta{n}^{-1}y=ta{n}^{-1}(\frac{x+y}{1-xy})$

$-\pi{}/2<ta{n}^{-1}x+ta{n}^{-1}y<\pi{}/2$

$tan(\alpha{}+\beta{})$

Text Transcription:

tan^-1 x+tan^-1 y=tan^-1(x+y/1-xy)

-pi/2<tan^-1 x+tan^-1 y<pi/2

tan(alpha+beta)

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