The tangent line to the curve y = (x 1)2 at the point(1, 4) has equation 4x + y = 0
Chapter 2, Problem 2(choose chapter or problem)
The tangent line to the curve \(y=(x-1)^{2}\) at the point \((−1, 4)\) has equation \(4x + y = 0\). Thus, the value of the limit
\(\lim \limits_{x \rightarrow-1} \frac{x^{2}-2 x-3}{x+1}\)
is _________.
Equation Transcription:
y = (x − 1)2
(−1, 4)
4x + y = 0
Text Transcription:
y = (x - 1)^2
(−1, 4)
4x + y = 0
lim_x right arrow -1 x^2 - 2x - 3/x + 1
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