The thin lens equation in physics is1s +1S = 1fwhere s is the object distance from the

Chapter 3, Problem 43

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The thin lens equation in physics is

\(\frac{1}{s}+\frac{1}{s}=\frac{1}{f}\)

where \(s\) is the object distance from the lens, \(S\) is the image distance from the lens, and \(f\) is the focal length of the lens. Suppose that a certain lens has a focal length of \(6 cm\) and that an object is moving toward the lens at the rate of \(2 cm/s\). How fast is the image distance changing at the instant when the object is \(10 cm\) from the lens? Is the image moving away from the lens or toward the lens?

Equation Transcription:

Text Transcription:

1/s + 1/s = 1/f

s

f

2 cm/s