The equilibrium constant k of a balanced chemical reactionchanges with the absolute
Chapter 3, Problem 48(choose chapter or problem)
The equilibrium constant k of a balanced chemical reaction changes with the absolute temperature T according to the law
\(k=k_{0} \exp \left(-\frac{q\left(T-T_{0}\right)}{2 T_{0} T}\right)\)
where \(k_{0}, q\), and \(T_{0}\) are constants. Find the rate of change of k with respect to T.
Equation Transcription:
Text Transcription:
k=k_0 exp(-q(T-T_0)/2T_0 T)
k_0, q
T_0
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