4346 Solve the initial-value problems. (a) dydx = 3 x, y(1) = 2(b) dydt = sin t + 1, y3=

Chapter 5, Problem 43

(choose chapter or problem)

Solve the initial-value problems.

(a) $\frac{d y}{d x}=\sqrt[3]{x}, y(1)=2$

(b) $\frac{d y}{d t}=\sin t+1, y\left(\frac{\pi}{3}\right)=\frac{1}{2}$

Equation Transcription:

$\frac{dy}{dx}=\sqrt[3]{x},\ y(1)=2$

$\frac{dy}{dt}=sin\ t+1,\ y(\frac{\pi{}}{3})=\frac{1}{2}$

$\frac{dy}{dx}=\frac{x+1}{\sqrt{x}},\ y(1)=0$

Text Transcription:

dy/dx = cube root x, y(1)=2

dy/dt = sin t+1, y(pi/3) =½

dy/dx =x+1/sqrt 1, y(1)=0

Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.

Login