(a) x2 dx1 + x6 ; u = x3(b) dxx1 (ln x)2; u = ln x

Chapter 5, Problem 11

(choose chapter or problem)

Evaluate the integrals using the indicated substitutions.

(a) $\int \frac{x^{2} d x}{1+x^{6}} ; u=x^{3}$

(b) $\int \frac{d x}{x \sqrt{1-(\ln x)^{2}}} ; u=\ln x$

Equation Transcription:

∫ $\frac{{x}^{2}dx}{1+{x}^{6}};u={x}^{3}$

∫ $\frac{dx}{x\sqrt{1-(ln\ x{)}^{2}}};u=ln\ x$

Text Transcription:

integral x^2 dx/1+ x^6 ;u=x^3

integral dx/x sqrt 1-(ln x)^2 ;u=ln x

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