1114 Solve the initial-value problem by separation of variables. dydt = 2t + 12y 2, y(0)

Chapter 8, Problem 13

(choose chapter or problem)

Solve the initial-value problem by separation of variables.

$\frac{d y}{d x}=\frac{2 t+1}{2 y-2}, y(0)=-1$

Equation Transcription:

$\frac{dy}{dx}\ \ =\ \ \frac{2t\ \ +\ \ 1}{2y\ \ -\ \ 2},\ \ y(0)\ \ =\ \ -1$

Text Transcription:

frac{dy}{dx} = frac{2t +1}{2y - 2}, y(0) = -1

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