Since n/[2(n + 1)](n 1)/(2n) = n2n2 1 >the sequence {(n 1)/(2n)} is strictly

Chapter 9, Problem 3

(choose chapter or problem)

Since $\frac{n /[2(n+1)]}{(n-1) /(2 n)}=\frac{n^{2}}{n^{2}-1}$ the sequence $\{(n-1) /(2 n)\}$ is strictly

Equation Transcription:

$\frac{n/\left[{2\left({n+1}\right)}\right]}{\left({n-1}\right)/\left({2n}\right)}=\frac{{n}^{2}}{{n}^{2}-1}$

$\left\{{\left({n-1}\right)/\left({2n}\right)}\right\}$

Text Transcription:

n/[2(n+1)] / (n-1)/(2n) = n^2 / n^2 - 1

{(n-1)/(2n)}

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