The Maclaurin series for ex2obtained by substituting x2for x in the seriesex = k=0xkk!is

Chapter 9, Problem 1

(choose chapter or problem)

The Maclaurin series for $e^{-x^{2}}$ obtained by substituting $-x^{2}$ for $x$ in the series

$e^{x}=\sum_{k=0}^{\infty} \frac{x^{k}}{k !}$

is $e^{-x^{2}}=\sum_{k=0}^{\infty}$__________.

Equation Transcription:

${e}^{-{x}^{2}}$

$-{x}^{2}$

${e}^{{x}^{\ }}=\sum\limits_{k=0}^{\infty{}}\frac{{x}^{k}}{k1}$

${e}^{-{x}^{2}}=\sum\limits_{k=0}^{\infty{}}$

Text transcription:

e^-x^2

-x^2

e^x = sum of k=0 infinity x^k/k!

e^-x^2 = sum of k=0 infinity

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