Show that among all parallelograms with perimeter l, asquare with sides of length l/4
Chapter 13, Problem 46(choose chapter or problem)
Show that among all parallelograms with perimeter \(l\), a square with sides of length \(l / 4\) has maximum area.
[Hint: The area of a parallelogram is given by the formula \(A=a b \sin \alpha\), where \(a\) and \(b\) are the lengths of two adjacent sides and \(\alpha\) is the angle between them.]
Equation Transcription:
Text Transcription:
l
l/4
A=ab sin alpha
a
b
alpha
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