Answer: 1720 Find the flux of the vector field F across in the directionof positive
Chapter 15, Problem 19(choose chapter or problem)
Find the flux of the vector field \(F\) across \(\sigma\) in the direction of positive orientation.
\(F(x, y, z)=\sqrt{x^{2}+y^{2}} ; \sigma\) is the portion of the cone
\(r(u, v)=u \cos v i+u \sin v j+2 u k\)
with \(0 \leq u \leq \sin v, 0 \leq v \leq \pi\).
Equation Transcription:
σ
σ
0 ≤ u ≤ sin v, 0 ≤ v ≤ π
Text Transcription:
F
Sigma
F(x, y, z) =e^-y i -y j + x sin zk;sigma
r(u, v) = u cos vi + u sin v j + 2uk
0 <= u <= sin v, 0 <= v <= pi
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer