Just as sometimes is the case when finding ordinary (i.e., unconstrained) critical
Chapter 4, Problem 15(choose chapter or problem)
Just as sometimes is the case when finding ordinary (i.e., unconstrained) critical points of functions, it can be difficult to solve a Lagrange multiplier problem because the system of equations that results may be prohibitively difficult to solve by hand. In Exercises 1519, use a computer algebra system to find the critical points of the given function f subject to the constraints indicated. (Note: You may find it helpful to provide numerical approximations in some cases.)f (x, y,z) = 3x y 4z, 3x + y 2x z = 1
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer