Show that the function f (x) = x2 + 3 for x < 1 10 x for 1 x 2 6x x2 for x > 2 is

Chapter 2, Problem 49

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Show that the function f (x) = x2 + 3 for x < 1 10 x for 1 x 2 6x x2 for x > 2 is continuous for x = 1, 2. Then compute the right- and left-hand limits at x = 1, 2, and determine whether f is left-continuous, rightcontinuous, or continuous at these points (Figure 17). 1 2 6 9 y = 10 x y = 6x x2 y = x2 + 3 x y

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