Show, by integrating the Maclaurin series for f (x) = 1 1 x2 , that for
Chapter 10, Problem 43(choose chapter or problem)
Show, by integrating the Maclaurin series for f (x) = 1 1 x2 , that for |x| < 1, sin1 x = x + n=1 1 3 5 (2n 1) 2 4 6 (2n) x2n+1 2n + 1
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