According to Coulombs Law, the attractive force between two electric charges of
Chapter 15, Problem 57(choose chapter or problem)
According to Coulombs Law, the attractive force between two electric charges of magnitude q1 and q2 separated by a distance r is kq1q2/r2 (k is a constant). Let F be the net force on a charged particle P of charge Q coulombs located d centimeters above the center of a circular disk of radius R, with a uniform charge distribution of density coulombs per square meter (Figure 21). By symmetry, F acts in the vertical direction. (a) Let R be a small polar rectangle of size r located at distance r. Show that R exerts a force on P whose vertical component is kQd (r2 + d2)3/2 r r (b) Explain why F is equal to the following double integral, and evaluate: F = kQd 2 0 R 0 r dr d (r2 + d2)3/2 FIGUR
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