As electric current moves through a wire (Fig. P7.14), heat generated by resistance is
Chapter 7, Problem 7.14(choose chapter or problem)
As electric current moves through a wire (Fig. P7.14), heat generated by resistance is conducted through a layer of insulation and then convected to the surrounding air. The steady-state temperature of the wire can be computed as T = Tair + q 2 1 k lnrw + ri rw + 1 h 1 rw + ri Determine the thickness of insulation ri(m) that minimizes the wires temperature given the following parameters: q = heat generation rate = 75 W/m, rw = wire radius = 6 mm, k = thermal conductivity of insulation = 0.17 W/(m K), h = convective heat transfer coefficient = 12 W/(m2 K), and Tair = air temperature = 293 K.
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