Falling Chain A portion of a uniform chain of length 8 ft is loosely coiled around a peg
Chapter 2, Problem 45(choose chapter or problem)
Falling Chain A portion of a uniform chain of length 8 ft is loosely coiled around a peg at the edge of a high horizontal platform and the remaining portion of the chain hangs at rest over the edge of the platform. See FIGURE 2.4.2. Suppose the length of the overhang is 3 ft, that the chain weighs 2 lb/ft, and that the positive direction is downward. Starting at t = 0 seconds, the weight of the overhanging portion causes the chain on the table to uncoil smoothly and fall to the floor. If x(t) denotes the length of the chain overhanging the table at time t > 0, then v = dx/dt is its velocity. When all resistive forces are ignored, it can be shown that a mathematical model relating v and x is
\(x v \frac{d v}{d x}+v^{2}=32 x\)
(a) Rewrite the model in differential form. Proceed as in Problems 31–36 and solve the DE by finding an appropriate integrating factor. Find an explicit solution v(x).
(b) Determine the velocity with which the chain leaves the platform.
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer