Answer: Suppose a cell is suspended in a solution containing a solute of constant

Chapter 2, Problem 34

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Suppose a cell is suspended in a solution containing a solute of constant concentration \(C_{s}\). Suppose further that the cell has constant volume V and that the area of its permeable membrane is the constant A. By Fick’s law the rate of change of its mass m is directly proportional to the area A and the difference \(C_{s}-C(t)\), where C(t) is the concentration of the solute inside the cell at any time t. Find \(C(t) \text { if } m=V \cdot C(t)\) and \(C(0)=C_{0}\).

See FIGURE 2.R.6.

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