The acceleration of a moving particle is a(t) "2 sin t i "2 cos t j. Given that the

Chapter 9, Problem 23

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The acceleration of a moving particle is \(\mathbf{a}(t)=\sqrt{2} \sin t \mathbf{i}+\sqrt{2} \cos t \mathbf{j}\). Given that the velocity and position of the particle at \(t=\pi / 4\) are \(\mathbf{v}(\pi / 4)=-\mathbf{i}+\mathbf{j}+\mathbf{k}\) and \(\mathbf{r}(\pi / 4)=\mathbf{i}+2 \mathbf{j}+(\pi / 4) \mathbf{k}\), respectively, what was the position of the particle at \(t=3 \pi / 4\)?

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