Use (1) and the fact that ( 6 5 ) 0.92 to evaluate # q 0 x 5 ex5 dx. [Hint: Let t x5 .]
Chapter 0, Problem 2(choose chapter or problem)
Use (1) and the fact that \(\Gamma\left(\frac{6}{5}\right)=0.92\) to evaluate \(\int_{0}^{\infty} x^{5} e^{-x^{5}} d x\). [Hint: Let \(t=x^{5}\).]
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer