Get answer: The table shows the mean (average) distances d of the planets from the sun

Chapter 1, Problem 26

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The table shows the mean (average) distances d of the planets from the sun (taking the unit of measurement to be the distance from the earth to the sun) and their periods T (time of revolution in years). Planet d T Mercury 0.387 0.241 Venus 0.723 0.615 Earth 1.000 1.000 Mars 1.523 1.881 Jupiter 5.203 11.861 Saturn 9.541 29.457 Uranus 19.190 84.008 Neptune 30.086 164.784 (a) Fit a power model to the data. (b) Keplers Third Law of Planetary Motion states that The square of the period of revolution of a planet is proportional to the cube of its mean distance from the sun. Does your model corroborate Keplers Third Law?

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