A 1.0kg object is released from rest 500 km (?300 miles)

Part (a)

Step 1 of 4

An object is released from the height above the Earth. We are going to find the impact speed as it hits the ground.

The mass of the object \(m=1 \mathrm{~kg}\)

The initial height \(\mathrm{y}=500 \mathrm{~km}=5 \times 10^{5} \mathrm{~m}\)

The acceleration due to gravity \(\mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^{2}\)

The gravitational constant \(\mathrm{G}=6.67 \times 10^{-11} \mathrm{~N} \cdot \mathrm{m}^{2} / \mathrm{kg}^{2}\)

The radius of the Earth \(\mathrm{R}=6.37 \times 10^{6} \mathrm{~m}\)

The mass of the Earth \(\mathrm{M}=5.98 \times 10^{24} \mathrm{~kg}\)

The initial speed of the object \(\mathrm{v}_{\mathrm{i}}=0\)

The final height \(y_{0}=0\)