Calculate each of the following quantities:(a) | Ch 3 - 16P

Principles of General Chemistry | 2nd Edition | ISBN: 9780073511085 | Authors: Martin S. Silberberg

Problem 16P Chapter 3

Principles of General Chemistry | 2nd Edition

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Principles of General Chemistry | 2nd Edition | ISBN: 9780073511085 | Authors: Martin S. Silberberg

Principles of General Chemistry | 2nd Edition

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Problem 16P Problem 16P

Calculate each of the following quantities:

(a) Mass in grams of 8.42 mol of chromium(III) sulfate decahydrate

(b) Mass in grams of 1.83×1024 molecules of dichlorine heptaoxide

(c) Number of moles and formula units in 6.2 g of lithium sulfate

(d) Number of lithium ions, sulfate ions, S atoms, and O atoms in the mass of compound in part (c)

Step-by-Step Solution:
Problem 16P:

Step 1:(a) Mass in grams of 8.42 mol of chromium(III) sulfate decahydrate

Here, we have to calculate the mass of   8.42 mol of chromium(III) sulfate decahydrate

 The molar mass of chromium(III) sulfate decahydrate, Cr2(SO4)3.10H2O = 572.4 g/mol

Given that,

The mol of Cr2(SO4)3.10H2O  = 8.42 mol

Therefore,

The mass of Cr2(SO4)3.10H2O   = 8.42 mol

                                                = 4819.608 g  = 4.82103 g of

Thus, the mass of 8.42 moles of  is 4.82103 g.

Step 2:

(b) Mass in grams of 1.83×1024 molecules of dichlorine heptoxide.

Here, we have to calculate the mass of 1.83×1024 molecules of dichlorine heptoxide.

We know that,

The molar mass of =182.9 g/mol

1.0 mole of = 6.0221023 molecules of

Therefore,

The moles of  =( 1.83×1024 molecules )

                        = 3.0388 moles of

Thus, the mass of = 3.0388 moles of

     = 555.807 g

                                         = 5.56 102 g of

Therefore, the mass of 1.83×1024 molecules of dichlorine heptoxide 5.56 102 g .

Step 3 of 4

Chapter 3, Problem 16P is Solved
Step 4 of 4

Textbook: Principles of General Chemistry
Edition: 2nd
Author: Martin S. Silberberg
ISBN: 9780073511085

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