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Potassium nitrate decomposes on heating, producing

Principles of General Chemistry | 2nd Edition | ISBN: 9780073511085 | Authors: Martin S. Silberberg ISBN: 9780073511085 71

Solution for problem 42P Chapter 3

Principles of General Chemistry | 2nd Edition

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Principles of General Chemistry | 2nd Edition | ISBN: 9780073511085 | Authors: Martin S. Silberberg

Principles of General Chemistry | 2nd Edition

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Problem 42P

Problem 42P

Potassium nitrate decomposes on heating, producing potassium oxide and gaseous nitrogen and oxygen:

To produce 56.6 kg of oxygen, how many (a) moles of KNO3 must be heated? (b) Grams of KNO3 must be heated?

Step-by-Step Solution:

Solution 42P

Here we will have to find out amount of KNO3 heated in moles and gram to form 56.6 kg of oxygen.

Potassium nitrate decomposes on heating, producing potassium oxide and gaseous nitrogen and oxygen:

4 KNO3 (s) → 2K2O (s) + 2N2 (g) + 5O2 (g)

Step 1

(a) Moles of KNO3 heated to produce 56.6 kg of oxygen

Given:

Mass of Oxygen = 56.6 kg = 56600 gram

Here 5 mole of O2 has formed from 4 moles of KNO3.

Molar mass of oxygen = 32.00 g/mole

We can use the conversion factor =

The mole of KNO3 heated can be calculated as,

56600 g O2  = 1415 or 1.42103 mol of KNO3

Thus  1.42103 mol of KNO3 is heated to produce 56.6 kg of oxygen.

Step 2 of 2

Chapter 3, Problem 42P is Solved
Textbook: Principles of General Chemistry
Edition: 2
Author: Martin S. Silberberg
ISBN: 9780073511085

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Potassium nitrate decomposes on heating, producing