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One of the first steps in the enrichment of uranium for
Chapter 4, Problem 45P(choose chapter or problem)
One of the first steps in the enrichment of uranium for use in nuclear power plants involves a displacement reaction between \(\mathrm{UO}_{2}\) and aqueous HF:
\(\mathrm{UO}_{2}(\mathrm{~s})+\mathrm{HF}(\mathrm{aq}) \rightarrow \mathrm{UF}_{4}(\mathrm{~s})+\mathrm{H}_{2} \mathrm{O}(\mathrm{l})\) [unbalanced]
How many liters of \(2.40 M\) HF will react with \(2.15 kg\) of \(\mathrm{UO}_{2}\)?
Equation Transcription:
UO2
UO2(s) + HF(aq) UF4(s) + H2O(l)
Text Transcription:
UO_2
UO_2(s) + HF(aq) UF_4(s) + H_2O(l)
2.40 M
2.15 kg
Questions & Answers
QUESTION:
One of the first steps in the enrichment of uranium for use in nuclear power plants involves a displacement reaction between \(\mathrm{UO}_{2}\) and aqueous HF:
\(\mathrm{UO}_{2}(\mathrm{~s})+\mathrm{HF}(\mathrm{aq}) \rightarrow \mathrm{UF}_{4}(\mathrm{~s})+\mathrm{H}_{2} \mathrm{O}(\mathrm{l})\) [unbalanced]
How many liters of \(2.40 M\) HF will react with \(2.15 kg\) of \(\mathrm{UO}_{2}\)?
Equation Transcription:
UO2
UO2(s) + HF(aq) UF4(s) + H2O(l)
Text Transcription:
UO_2
UO_2(s) + HF(aq) UF_4(s) + H_2O(l)
2.40 M
2.15 kg
ANSWER:
Solution 45P
Here, we have to calculate the volume of Hydrogen fluoride reacts with UO2.
Step 1 of 2
The given chemical reaction:
UO2(s) + HF(aq) UF4 (s) + H2O(l) [ unbalanced]
Let’s balance the given chemical reaction.
UO2(s) + 4HF(aq) UF4 (s) + 2H2O(l)
From the balanced chemical reaction 4 moles of HF reacts with UO2 and produce 1 mole of UF4 and 2 moles of water.
Let’s calculate the moles of HF.
Given:
Molarity of HF = 2.40M
Mass of UO2 = 2.15 kg.
Let’s write the equality and conversion factors.
1 kg = 1000g
1 mol of UO2 = 270.0 g of UO2
From the equation
4 mol of HF = 1 mol UO2
So, the conversion factors are ,
and
2.15 kg
= 31.85 mol of HF
Therefore, moles of HF is 31.85 mol.
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