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Silver bromide is used to coat ordinary black-and-white
Chapter 5, Problem 68P(choose chapter or problem)
Silver bromide is used to coat ordinary black-and-white photographic film, while high-speed film uses silver iodide.
When \(50.0 mL\) of \(5.0 \mathrm{~g} / \mathrm{L} \ \mathrm{AgNO}_{3}\) is added to a coffee-cup calorimeter containing \(50.0 mL\) of \(5.0 g/L NaI\), with both solutions at \(25^{\circ} \mathrm{C}\), what mass of AgI forms?
Use Appendix B to find \(\Delta \mathrm{H}_{\mathrm{rxn}}^{\circ}\).
What is \(\Delta T_{\text {soln }}\) (assume the volumes are additive and the solution has the density and specific heat capacity of water)?
Equation Transcription:
5.0 g/L AgNO3
25°C
H°rxn
Tsoln
Text Transcription:
50.0 mL
5.0 g/L AgNO_3
5.0 g/L NaI
25°C
Delta H°_rxn
Delta T_soln
Questions & Answers
QUESTION:
Silver bromide is used to coat ordinary black-and-white photographic film, while high-speed film uses silver iodide.
When \(50.0 mL\) of \(5.0 \mathrm{~g} / \mathrm{L} \ \mathrm{AgNO}_{3}\) is added to a coffee-cup calorimeter containing \(50.0 mL\) of \(5.0 g/L NaI\), with both solutions at \(25^{\circ} \mathrm{C}\), what mass of AgI forms?
Use Appendix B to find \(\Delta \mathrm{H}_{\mathrm{rxn}}^{\circ}\).
What is \(\Delta T_{\text {soln }}\) (assume the volumes are additive and the solution has the density and specific heat capacity of water)?
Equation Transcription:
5.0 g/L AgNO3
25°C
H°rxn
Tsoln
Text Transcription:
50.0 mL
5.0 g/L AgNO_3
5.0 g/L NaI
25°C
Delta H°_rxn
Delta T_soln
ANSWER:
Problem 68P
Silver bromide is used to coat ordinary black-and-white photographic film, while high-speed film uses silver iodide.
(a) When 50.0 ml of 5.0 g/L is added to a coffee-cup calorimeter containing 50.0 mL of 5.0 g/L NaI, with both solutions at 25 , what mass of AgI forms?
(b) Use Appendix B to find .
(c) What is (assume the volumes are additive and the solution has the density and specific heat capacity of water)?
Step by step solution
Step 1 of 3
(a) Balanced thermochemical equation for the reactants is given by
From the balanced chemical equation, one mole of reacts with one mole of NaI to give one mole of AgI.
Molar mass of = 169.91 g/mol
Mass of = 0.05 L x 5.0 g/L
= 0.25 g
Number of moles of
= 0.00147 moles
Molar mass of NaI = 149.9 g/mol
Mass of NaI = 0.05L x 5.0 g/L
= 0.25 g
Number of moles of
= 0.00166
is the limiting reagent.
1 mole of forms one mole of AgI.
Then 0.00147 moles of forms 0.00147 moles of AgI.
Molar mass of AgI = 234.8 g/ mol
Mass of AgI formed = 234.8 g/ mol x 0.00147 moles
= 0.345 g