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How many grams of potassium chlorate decompose to
Chapter 6, Problem 44P(choose chapter or problem)
How many grams of potassium chlorate decompose to potassium chloride and \(638 mL\) of \(\mathrm{O}_{2}\) at \(128^{\circ} \mathrm{C}\) and \(752 torr\)?
\(2 \mathrm{KCIO}_{3}(s) \rightarrow 2 \mathrm{KCI}(s)+3 \mathrm{O}_{2}(g)\)
Equation Transcription:
O2
128°C
Text Transcription:
638 mL
O_2
128°C
752 torr
2KCIO_3(s) rightarrow 2KCI(s)+3O_2(g)
Questions & Answers
QUESTION:
How many grams of potassium chlorate decompose to potassium chloride and \(638 mL\) of \(\mathrm{O}_{2}\) at \(128^{\circ} \mathrm{C}\) and \(752 torr\)?
\(2 \mathrm{KCIO}_{3}(s) \rightarrow 2 \mathrm{KCI}(s)+3 \mathrm{O}_{2}(g)\)
Equation Transcription:
O2
128°C
Text Transcription:
638 mL
O_2
128°C
752 torr
2KCIO_3(s) rightarrow 2KCI(s)+3O_2(g)
ANSWER:
Solution 44P
Here we have to find out the mass of potassium chlorate in grams.
Step 1
Given:
The balanced chemical equation for decomposition of potassium chlorate is given below,
2 KClO3 (s) → 2KCl (s) + 3O2 (g)
Volume of O2 = 638 mL of O2 at = 638 mL = 0.638 L
Temperature = 128°C = 273 + 128 = 401 K
Pressure = 752 torr = 752 torr = 0.989 atm
n =
Where P = pressure
V = Volume
T = temperature
n = number of moes
R = gas constant i.e 0.0821 L atm mol-1 k-1
Now substituting the values, the number of moles can be calculated as,
n =
= = 0.019 mol O2