Roasting galena [lead(II) sulfide] is an early step in the

Chapter 6, Problem 52P

(choose chapter or problem)

Get Unlimited Answers
QUESTION: Problem 52P

Roasting galena [lead(II) sulfide] is an early step in the industrial isolation of lead. How many liters of sulfur dioxide, measured at STP, are produced by the reaction of 3.75 kg of galena with 228 L of oxygen gas at 220°C and 2.0 atm? Lead(II) oxide also forms.

Questions & Answers

QUESTION: Problem 52P

Roasting galena [lead(II) sulfide] is an early step in the industrial isolation of lead. How many liters of sulfur dioxide, measured at STP, are produced by the reaction of 3.75 kg of galena with 228 L of oxygen gas at 220°C and 2.0 atm? Lead(II) oxide also forms.

ANSWER:

Problem 52P

Roasting galena [lead(II) sulfide] is an early step in the industrial isolation of lead. How many liters of sulfur dioxide, measured at STP, are produced by the reaction of 3.75 kg of galena with 228 L of oxygen gas at 220°C and 2.0 atm? Lead(II) oxide also forms.

Solution 52P:

Here, we are going to calculate the volume of SO2 which is produced by the reaction of galena with oxygen.

Step 1:

Calculation of the mol of PbS(s).

The balanced equation of the reaction is

Given that

The mass of PbS = 3.75 kg = 3.73

The molar mass of Pbs=239.3 g/mol

Thus, the mol of PbS = (3.73 PbS) = 15.587 mol PbS

Add to cart


Study Tools You Might Need

Not The Solution You Need? Search for Your Answer Here:

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back