Solution Found!
Roasting galena [lead(II) sulfide] is an early step in the
Chapter 6, Problem 52P(choose chapter or problem)
Roasting galena [lead(II) sulfide] is an early step in the industrial isolation of lead. How many liters of sulfur dioxide, measured at STP, are produced by the reaction of 3.75 kg of galena with 228 L of oxygen gas at 220°C and 2.0 atm? Lead(II) oxide also forms.
Questions & Answers
QUESTION: Problem 52P
Roasting galena [lead(II) sulfide] is an early step in the industrial isolation of lead. How many liters of sulfur dioxide, measured at STP, are produced by the reaction of 3.75 kg of galena with 228 L of oxygen gas at 220°C and 2.0 atm? Lead(II) oxide also forms.
ANSWER:
Problem 52P
Roasting galena [lead(II) sulfide] is an early step in the industrial isolation of lead. How many liters of sulfur dioxide, measured at STP, are produced by the reaction of 3.75 kg of galena with 228 L of oxygen gas at 220°C and 2.0 atm? Lead(II) oxide also forms.
Solution 52P:
Here, we are going to calculate the volume of SO2 which is produced by the reaction of galena with oxygen.
Step 1:
Calculation of the mol of PbS(s).
The balanced equation of the reaction is
Given that
The mass of PbS = 3.75 kg = 3.73
The molar mass of Pbs=239.3 g/mol
Thus, the mol of PbS = (3.73 PbS) = 15.587 mol PbS