What is the ratio of effusion rates for O2 and Kr?

Here, we are going to find out the ratio of effusion rates for both the gases \(\mathrm{O}_{2}\) and \(\mathrm{Kr}\).

Step 1 of 3

Effusion is a process by which a gas escapes from its container through a tiny hole into an evacuated space.

Graham's law of effusion:

It states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass.

Rate of effusion \(\alpha \frac{\frac{1}{\sqrt{\mu}}}{\cdots}\)

Where \(\mu\) is the molar mass.

Thus,

\(\begin{aligned}\text { Rateo }_{2} &=\frac{1}{\sqrt{\mu_{O 2}}} \ldots-(2) \\\text { Rate }_{K r} &=\frac{1}{\sqrt{\mu_{K r}}} \ldots(3)\end{aligned}\)