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A baker uses sodium hydrogen carbonate (baking soda) as
Chapter 6, Problem 70P(choose chapter or problem)
A baker uses sodium hydrogen carbonate (baking soda) as the leavening agent in a banana-nut quickbread. The baking soda decomposes according to two possible reactions:
(1) \(2 \mathrm{NaHCO}_{3}(s) \longrightarrow \mathrm{Na}_{2} \mathrm{CO}_{3}(s)+\mathrm{H}_{2} \mathrm{O}(l)+\mathrm{CO}_{2}(g)\)
(2) \(\mathrm{NaHCO}_{3}(s)+\mathrm{H}^{+}(a q) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{CO}_{2}(g)+\mathrm{Na}^{+}(a q)\)
Calculate the volume (in mL) of \(\mathrm{CO}_{2}\) that forms at \(200^{\circ} \mathrm{C}\) and \(0.975 atm\) per gram of \(\mathrm{NaHCO}_{3}\) by each of the reaction processes.
Equation Transcription:
CO2
200°C
NaHCO3
Text Transcription:
2NaHCO_3(s) rightarrow Na_2CO_3(s) + H_2O(l)+CO_2(g)
NaHCO_3(s) + H^+(aq) rightarrow H_2O(l)+CO_2(g)+Na^+(aq)
CO_2
200°C
0.975 atm
NaHCO_3
Questions & Answers
QUESTION:
A baker uses sodium hydrogen carbonate (baking soda) as the leavening agent in a banana-nut quickbread. The baking soda decomposes according to two possible reactions:
(1) \(2 \mathrm{NaHCO}_{3}(s) \longrightarrow \mathrm{Na}_{2} \mathrm{CO}_{3}(s)+\mathrm{H}_{2} \mathrm{O}(l)+\mathrm{CO}_{2}(g)\)
(2) \(\mathrm{NaHCO}_{3}(s)+\mathrm{H}^{+}(a q) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{CO}_{2}(g)+\mathrm{Na}^{+}(a q)\)
Calculate the volume (in mL) of \(\mathrm{CO}_{2}\) that forms at \(200^{\circ} \mathrm{C}\) and \(0.975 atm\) per gram of \(\mathrm{NaHCO}_{3}\) by each of the reaction processes.
Equation Transcription:
CO2
200°C
NaHCO3
Text Transcription:
2NaHCO_3(s) rightarrow Na_2CO_3(s) + H_2O(l)+CO_2(g)
NaHCO_3(s) + H^+(aq) rightarrow H_2O(l)+CO_2(g)+Na^+(aq)
CO_2
200°C
0.975 atm
NaHCO_3
ANSWER:Solution 70P
Here, we have to calculate the moles of CO2 in two possible reactions of baking soda decomposition.
Step 1 of 2
The baking soda decomposes into two possible reactions.
-
2NaHCO3(s)
Na2CO3(s) + H2O(l) + CO2(g)
First, let’s calculate the number of moles of NaHCO3 in 1g of Baking Soda.
Number of mole of NaHCO3 =
=
= 0.0119 mol
Therefore, moles of NaHCO3 is 0.0119 mol.
Let’s calculate the number of moles of CO2 Produced.
From the given chemical equation
2 moles of NaHCO3 produce 1 mole of CO2
Mole- mole factor is
= 0.0119 mol NaHCO3
= 0.00595 mol of CO2.
Therefore, moles of CO2 is 0.00595 mol.
Let’s calculate the volume of CO2 gas.
Write the Ideal gas equation
PV = nRT
Rearrange the formula is as follows.
V =
Given
n= 0.00595 mol
R = 0.821 L.atm.mol-1.K-1.
T = 473 k
P = 0.975 atm.
Substitute the values.
=
= 0.237 L
Therefore, volume of CO2 is 0.237 L.
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