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The Hawaiian volcano Kilauea emits an average of 1.5×103
Chapter 6, Problem 92P(choose chapter or problem)
The Hawaiian volcano Kilauea emits an average of 1.5×103 m3 of gas each day, when corrected to 298 K and 1.00 atm. The mixture contains gases that contribute to global warming and acid rain, and some are toxic. An atmospheric chemist analyzes a sample and finds the following mole fractions: 0.4896 CO2, 0.0146 CO, 0.3710 H2O, 0.1185 SO2, 0.0003 S2,0.0047 H2,0.0008 HC1, and 0.0003 H2S. How many metric tons (t) of each gas are emitted per year (1t = 1000 kg)?
Questions & Answers
QUESTION: Problem 92P
The Hawaiian volcano Kilauea emits an average of 1.5×103 m3 of gas each day, when corrected to 298 K and 1.00 atm. The mixture contains gases that contribute to global warming and acid rain, and some are toxic. An atmospheric chemist analyzes a sample and finds the following mole fractions: 0.4896 CO2, 0.0146 CO, 0.3710 H2O, 0.1185 SO2, 0.0003 S2,0.0047 H2,0.0008 HC1, and 0.0003 H2S. How many metric tons (t) of each gas are emitted per year (1t = 1000 kg)?
ANSWER:
Solution 92P:
Here, we are going to calculate the metric tons of each gas emitted per year.
Step 1:
From an ideal gas equation,
----(1)
Where P is the pressure, V is the volume and T is the temperature and n is the mole of the gas.
Given that
P, pressure =1.0 atm
T, temperature = 2980 K
V, volume =1.5×103 m3 =1.5×106 L
For the calculation of n =?
Thus,
----(1)
== 61.31
mol of gases
Therefore, total moles of gases =61.31moles of gases