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A 6.0-L flask contains a mixture of methane (CH4), argon,
Chapter 6, Problem 101P(choose chapter or problem)
A 6.0-L flask contains a mixture of methane (CH4), argon, and helium at 45°C and 1.75 atm. If the mole fractions of helium and argon are 0.25 and 0.35, respectively, how many molecules of methane are present?
Questions & Answers
QUESTION: Problem 101P
A 6.0-L flask contains a mixture of methane (CH4), argon, and helium at 45°C and 1.75 atm. If the mole fractions of helium and argon are 0.25 and 0.35, respectively, how many molecules of methane are present?
ANSWER:
Solution 101P:
Here, we are going to find out the number of molecules of methane present in the mixture.
Step 1:
Calculation of mole fraction of methane.
We know that,
The mole fraction of a molecule is related with the partial pressure and total pressure of the gas molecule. It is as follows
----(1)
Where is the partial pressure of the gas molecule
is the mole fraction of gas molecule
is the total pressure of the mixture.
Given that,
Thus, the mole fraction of +
)
= 1-(0.25 +0.35)
= 1.0 -0.6
=0.4
Thus, the mole fraction of methane is 0.4.