Solution Found!
What is the number of atoms per unit cell for each
Chapter 11, Problem 67P(choose chapter or problem)
What is the number of atoms per unit cell for each metal?
(a) Polonium, \(Po\) (b) Manganese, \(Mn\) (c) Silver, \(Ag\)
Equation Transcription:
Text Transcription:
Po
Mn
Ag
Questions & Answers
QUESTION:
What is the number of atoms per unit cell for each metal?
(a) Polonium, \(Po\) (b) Manganese, \(Mn\) (c) Silver, \(Ag\)
Equation Transcription:
Text Transcription:
Po
Mn
Ag
ANSWER:
Solution 67P
Here we have to find out the number of atoms present per unit cell for each metal.
Step 1
(a) Polonium, Po
The structure of Po shows a simple cubic unit cell. In simple cubic unit cell, 8 atoms are present in 8 corners of the unit cell and each atom is shared by 8 unit cells. Therefore, the contribution of each corner atom to each unit cell is ⅛.
Total atom per unit cell can be calculated as,
⅛ 8 = 1
Therefore the number of atoms in simple cubic unit cell of Po atom is 1.