Gold occurs in seawater at an average concentration of 1.1

Chapter 14, Problem 85P

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QUESTION:

Problem 85P

Gold occurs in seawater at an average concentration of 1.1 × 10?2 ppb. How many liters of seawater must be processed to recover 1 troy ounce of gold, assuming 81.5% efficiency (d of seawater = 1.025 g/mL; 1 troy ounce = 31.1 g)?

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QUESTION:

Problem 85P

Gold occurs in seawater at an average concentration of 1.1 × 10?2 ppb. How many liters of seawater must be processed to recover 1 troy ounce of gold, assuming 81.5% efficiency (d of seawater = 1.025 g/mL; 1 troy ounce = 31.1 g)?

ANSWER:

Solution 85P

Here, we are going to determine the volume of seawater.

Step 1:

Given that,

The concentration of gold = 1.1 × 10-2 ppb

Density of the sea water = 1.025 g/mL

We know that,

----(1)

Calculation of the mass of solvent:

                    = 1.025 g/mL  ----(2)


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