Solution Found!
At a particular temperature, Kc = 6.5 × 102 for Calculate
Chapter 17, Problem 14P(choose chapter or problem)
At a particular temperature, \(K_{\mathrm{c}}=6.5 \times 10^{2}\) for
Calculate 𝐾c for each of the following reactions:
Equation Transcription:
𝐾c = 6.5102
Text Transcription:
𝐾_c = 6.5 times 10^2
Questions & Answers
QUESTION:
At a particular temperature, \(K_{\mathrm{c}}=6.5 \times 10^{2}\) for
Calculate 𝐾c for each of the following reactions:
Equation Transcription:
𝐾c = 6.5102
Text Transcription:
𝐾_c = 6.5 times 10^2
ANSWER:
Solution 14P:
Here, we are going to calculate the Kc for the reaction.
Step 1:
Given that,
2NO(g) + 2H2(g) N2(g) + 2H2O(g), Kc = 6.5 × 102
And, = 6.5 × 102 ---(1)
Now, for the reaction (a) KC1 would be
NO(g) + H2 (g) N2(g) + H2O
-----(2)
Now, squaring the equation (2) by 2 we get
----(3)
Hence, Dividing the equation (1) by (3) we get,
= 25.5
Therefore, the KC1 for the reaction (a) is 25.5