Answer: In 5053, for the function f define a sequence recursivelyby xn = f(xn1) for n >
Chapter 9, Problem 52(choose chapter or problem)
In 5053, for the function f define a sequence recursivelyby xn = f(xn1) for n > 1 and x1 = a. Dependingon f and the starting value a, this sequence may converge to alimit L. If L exists, it has the property that f(L) = L. For thefunctions and starting values given, use a calculator to see ifthe sequence converges. [To obtain the terms of the sequence,repeatedly push the function button.]f(x) = sin x, a = 1
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer