According to Coulombs Law, the electric field E at thepoint r due to a charge q at the
Chapter 19, Problem 37(choose chapter or problem)
According to Coulombs Law, the electric field E at thepoint r due to a charge q at the point r 0 is given byE (r ) = q (r r 0)r r 03 .Suppose S is a closed, outward-oriented surface and thatr 0 does not lie on S. Use to show thatSE dA =4q if q lies inside S,0 if q lies outside S.
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