Solution: Pendulum The period of a pendulum of length is where is the acceleration due
Chapter 13, Problem 38(choose chapter or problem)
The period T of a pendulum of length L is
\(T=\frac{2 \pi \sqrt{L}}{\sqrt{g}}\)
where g is the acceleration due to gravity. A pendulum is moved from the Canal Zone, where g = 32. 09 feet per second per second, to Greenland, where g = 32. 23 feet per second per second. Because of the change in temperature, the length of the pendulum changes from 2. 5 feet to 2. 48 feet. Approximate the change in the period of the pendulum.
Text Transcription:
T = 2 \pi sqrt{L} / sqrt{g}
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