Answer: Horizontal Tangent Plane In Exercises 4146, find the point(s) on the surface at
Chapter 13, Problem 44(choose chapter or problem)
In Exercises 41 - 46, find the point(s) on the surface at which the tangent plane is horizontal.
\(z=4 x^{2}+4 x y-2 y^{2}+8 x-5 y-4\)
Text Transcription:
z = 4x^2 + 4xy - 2y^2 + 8x - 5y - 4
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