A solution is made 1.1 * 10-3 M in Zn(NO3)2 and 0.150 M in NH3. After the solution
Chapter 16, Problem 109(choose chapter or problem)
A solution is made \(1.1 \times 10^{-3} \mathrm{M}\) in \(\mathrm{Zn}\left(\mathrm{NO}_{3}\right)_{2}\) and 0.150 M in \(\mathrm{NH}_{3}\). After the solution reaches equilibrium, what concentration of \(\mathrm{Zn}^{2+}(a q)\) remains?
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer