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Two particles move along an x axis. The position of

Chapter , Problem 70

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QUESTION:

Two particles move along an x axis. The position of particle 1 is given by \(x=6.00 t^{2}+3.00 t+2.00\) (in meters and seconds); the acceleration of particle 2 is given by a = −8.00t (in meters per second squared and seconds) and, at t = 0, its velocity is 20 m/s. When the velocities of the particles match, what is their velocity?

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QUESTION:

Two particles move along an x axis. The position of particle 1 is given by \(x=6.00 t^{2}+3.00 t+2.00\) (in meters and seconds); the acceleration of particle 2 is given by a = −8.00t (in meters per second squared and seconds) and, at t = 0, its velocity is 20 m/s. When the velocities of the particles match, what is their velocity?

ANSWER:

Step 1 of 4We need to find out when the velocities of the particle one and two match and their velocity.The position of the particle one is given by,So the velocity of the particle one is, ...........................(1)

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