Graph and label the given points by hand.1-5, 12, 15, 12, 12, 32, 12, -12, 10, 12

Spans Part 2 Monday, October 10, 2016 7:04 PM 2 All vectorsin R is: Any combination of vectors is possible therefore: 2 Is this true of any two vectors in R Has solutions only when b - a = 0 or a = b. Spans Continued Wednesday, October 12, 2016 3:21 PM Theorem:Let u 1 u ,mu be vectorsin R n If u is in spa1(u , …m, u ) then s1an(u ,m… , u ) = sp1n(u, m , … , u ) Proof: First we show that any vector in the span1u , …m, u ) is in the spa1(u, um, … , u ) Let v be in the span1u , … m u ) so v = ▯ ▯ + ▯▯ ▯▯ + ⋯+ ▯ ▯ ▯▯ ALSO v = 0▯ + ▯▯ ▯ + ▯▯ ▯ + ⋯+ ▯ ▯▯ ▯▯ Therefore v is also in the span(1, u , m , u ).