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A 4.8-ft-long steel wire of 1 4 -in.-diameter is subjected
Chapter 2, Problem 2.2(choose chapter or problem)
A 4.8-ft-long steel wire of \(\frac{1}{4}-\text { in. }\)-diameter is subjected to a 750-lb tensile load. Knowing that \(E=29 \times 10^{6} \mathrm{psi}\), determine (a) the elongation of the wire, (b) the corresponding normal stress.
Questions & Answers
QUESTION:
A 4.8-ft-long steel wire of \(\frac{1}{4}-\text { in. }\)-diameter is subjected to a 750-lb tensile load. Knowing that \(E=29 \times 10^{6} \mathrm{psi}\), determine (a) the elongation of the wire, (b) the corresponding normal stress.
ANSWER:Step 1 of 5
We will find the elongation of the wire due to applied load using the formula for elongation due to single axial load. The tensile stress can also be computed by dividing the applied force by the cross sectional area.
Given data are
Length of wire: L = 4.8 ft
Diameter of wire: D = 0.25 in
Applied load: P = 750 lb
Modulus of elasticity:
