Solve.12+2x = 13+3x
Step 1 of 3
Displacement, velocity and acceleration Ex. a particle moves back and forth along a straight line. Its displacement at time t ( t is in seconds, s(t)) is in feet is s(t)=t^3 12t^2 +36t a. What is the particle’s velocity at time t v(t) = s’(t) =3t^2 24t + 36 ft/sec b. When is the particle at rest Solve v(t)= 3t^2 24t + 36 = 0 Divide by three t^2 8t + 12 = 0 factor (t 2)(t + 6) = 0 t = 2 sec, 6 sec c. what is the initial velocity Plug in 0 for t v(0) = 36 ft/sec d. what is the displacement at t =2 and t =6 sec Plug in 2 and 6 to the original function s(2) = 32 ft s(6) = 0ft Line graph Graph e. When is
Textbook: College Algebra: Graphs and Models
Author: Marvin L. Bittinger, Judith A. Beecher, David J. Ellenbogen, Judith A. Penna
The answer to “Solve.12+2x = 13+3x” is broken down into a number of easy to follow steps, and 3 words. Since the solution to 5 from 3.4 chapter was answered, more than 237 students have viewed the full step-by-step answer. This full solution covers the following key subjects: . This expansive textbook survival guide covers 65 chapters, and 5235 solutions. This textbook survival guide was created for the textbook: College Algebra: Graphs and Models, edition: 5. College Algebra: Graphs and Models was written by and is associated to the ISBN: 9780321783950. The full step-by-step solution to problem: 5 from chapter: 3.4 was answered by , our top Math solution expert on 03/09/18, 08:04PM.