One solution to the initial-value problem dy dx = 2 3 (y 1) 1/2, y(1) = 1 is y(x) = 1
Chapter 1, Problem 16(choose chapter or problem)
One solution to the initial-value problem dy dx = 2 3 (y 1) 1/2, y(1) = 1 is y(x) = 1. Determine another solution to this initialvalue problem. Does this contradict the existence and uniqueness theorem (Theorem 1.3.2)? Explain.
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