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An 8.0 kg object is moving in the positive direction of an
Chapter , Problem 16(choose chapter or problem)
An 8.0 kg object is moving in the positive direction of an x axis.When it passes through x = 0, a constant force directed along the axis begins to act on it. Figure 7-29 gives its kinetic energy K versus position x as it moves from x = 0 to x = 5.0 m; \(K_{0}=30.0 J\). The force continues to act. What is v when the object moves back through \(x=-3.0 \mathrm{~m}\)?
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QUESTION:
An 8.0 kg object is moving in the positive direction of an x axis.When it passes through x = 0, a constant force directed along the axis begins to act on it. Figure 7-29 gives its kinetic energy K versus position x as it moves from x = 0 to x = 5.0 m; \(K_{0}=30.0 J\). The force continues to act. What is v when the object moves back through \(x=-3.0 \mathrm{~m}\)?
ANSWER:Step 1 of 6:
We are asked to find the velocity with which the object of mass 8kg moves back through x = -3m. The object is moving through the positive direction of the axis under the influence of a force.
Given:
At x = 0m, the kinetic energy is \(K_{o}=30.0 \mathrm{~J}\)
At x = 5m, the kinetic energy is \(K_{1}=0 \mathrm{~J}\)